A 2 kg block on a horizontal surface has kinetic friction with μk = 0.3. What is the magnitude of the kinetic friction force?

Study for the Newton's Laws of Motion Test. Engage with multiple choice and interactive questions, each hinting at concepts with detailed explanations. Master the principles and ace your exam!

Multiple Choice

A 2 kg block on a horizontal surface has kinetic friction with μk = 0.3. What is the magnitude of the kinetic friction force?

Explanation:
Frictional force exercising kinetic friction follows F_k = μk N. On a horizontal surface, the normal force equals the weight, so N = mg. With m = 2 kg and g ≈ 9.8 m/s^2, N = 2 × 9.8 = 19.6 N. Then F_k = μk N = 0.3 × 19.6 = 5.88 N. So the magnitude is 5.88 newtons, directed opposite the motion. The other numbers would require a different μk or a different normal force, but with the given data this is the correct result.

Frictional force exercising kinetic friction follows F_k = μk N. On a horizontal surface, the normal force equals the weight, so N = mg. With m = 2 kg and g ≈ 9.8 m/s^2, N = 2 × 9.8 = 19.6 N. Then F_k = μk N = 0.3 × 19.6 = 5.88 N. So the magnitude is 5.88 newtons, directed opposite the motion. The other numbers would require a different μk or a different normal force, but with the given data this is the correct result.

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